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Finding the minimum distance from ", Cell[BoxData[ \(TraditionalForm\`\(P\_0\ \)\)]], " to the ellipse is a well-known problem. One can easily show that the \ minimum distance path lies along a normal line to the ellipse, passing \ through ", Cell[BoxData[ \(TraditionalForm\`P\_0\)]], ". This paper deals with a study of all the normal lines drawn from point \ ", Cell[BoxData[ \(TraditionalForm\`\(P\_0\ \)\)]], " to the ellipse. We have used the computer algebra system ", StyleBox["Mathematica", FontSlant->"Italic"], " to illustrate and discover several aspects of these normal lines. ", StyleBox["Mathematica", FontSlant->"Italic"], " can be used in contemporary mathematical research and educaiton in more \ than one way: as a computational, visualization, experimentation and a \ conjecture forming tool (see [4]-[14]). The paper well illustrates such \ usage via a study of the normal lines to the ellipse. We used ", StyleBox["Matheamtica", FontSlant->"Italic"], " version 3.0 on a ", StyleBox["Windows", FontSlant->"Italic"], " 95 platform. Some good references on ", StyleBox["Mathematica", FontSlant->"Italic"], " are [2], [16], [18] and [19]. " }], "Text", TextJustification->1], Cell[CellGroupData[{ Cell["1. Introduction", "Section", FontColor->RGBColor[0, 0, 1]], Cell[TextData[{ "Consider the ellipse given by the following equation, where ", Cell[BoxData[ \(TraditionalForm\`a > b > 0\)]], ":\n\n \ ", Cell[BoxData[ \(TraditionalForm\`\(\ x\^2\)\)]], "/", Cell[BoxData[ \(TraditionalForm\`a\^2 + y\^2/b\^2 = 1\)]], " \ (1.1)\n\nSuppose ", Cell[BoxData[ \(TraditionalForm\`\(P\_0\)(x\_0, y\_0)\)]], " is an arbitrary point on the plane. In this introductory section of the \ paper, we will investigate on the number of normal lines that can be drawn \ from ", Cell[BoxData[ \(TraditionalForm\`P\_0\)]], " to the ellipse. Most of the material in the introduction can also be \ found in [14], but in order to make this paper self contained as much as \ possible, we will also include it here.\n\nSuppose ", Cell[BoxData[ \(TraditionalForm\`\(P\_0\) P\)]], " is a normal line drawn from to the ellipse (1.1), meeting the ellipse at \ the point ", Cell[BoxData[ \(TraditionalForm\`P(a\ Cos\ \[Theta], \ b\ Sin\ \[Theta])\)]], ", where 0 \[LessEqual] \[Theta] < 2\[Pi] . \ " }], "Text", CellMargins->{{9, Inherited}, {Inherited, Inherited}}, TextAlignment->Left, TextJustification->1], Cell[GraphicsData["PostScript", "\<\ %! %%Creator: Mathematica %%AspectRatio: .66667 MathPictureStart /Mabs { Mgmatrix idtransform Mtmatrix dtransform } bind def /Mabsadd { Mabs 3 -1 roll add 3 1 roll add exch } bind def %% Graphics %%IncludeResource: font Courier %%IncludeFont: Courier /Courier findfont 10 scalefont setfont % Scaling calculations 0.426333 0.0670873 0.284222 0.0670873 [ [ 0 0 0 0 ] [ 1 .66667 0 0 ] ] MathScale % Start 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o`@00003oooo0`0000ooool01@000?ooooooooooo`00001?oooo001;oooo1P0000koool00`000?oo ooooo`0"], ImageRangeCache->{{{186.688, 329.688}, {157, 62.125}} -> {-25.815, 2.27048, 0.0833908, 0.083794}}], Cell[TextData[{ " ", StyleBox["Fig 1.1.", FontWeight->"Bold"], " Normal Line to an Ellipse" }], "Text", CellMargins->{{9, Inherited}, {Inherited, Inherited}}, TextAlignment->Left, TextJustification->1], Cell[TextData[{ "One can find the slope of the line ", Cell[BoxData[ \(TraditionalForm\`\(P\_0\) P\)]], " in two different ways: \n\n \ slope of ", Cell[BoxData[ \(TraditionalForm\`\(P\_0\) P\)]], " = ", Cell[BoxData[ \(TraditionalForm \`\((y\_0 - b\ Sin\ \[Theta])\)/\((x\_0 - a\ Cos\ \[Theta])\)\)]], " \t (1.2)\n \ \nOne can implicitly differentiate the equation (1.1) with \ respect to ", Cell[BoxData[ \(TraditionalForm\`x\)]], " , to obtain the slope of the tangent line at ", Cell[BoxData[ \(TraditionalForm\`\((x, \ y)\)\)]], ":\n\n ", Cell[BoxData[ \(TraditionalForm\`d\ y/d\ x = \(-b\^2\) x/\((\(a\^2\) y)\)\)]], " \t\t (1.3)\n \n\ One can evaluate equation (1.3) at ", Cell[BoxData[ \(TraditionalForm\`P(a\ Cos\ \[Theta], \ b\ Sin\ \[Theta])\)]], " to find the slope of the tangent line to the ellipse at ", Cell[BoxData[ \(TraditionalForm\`P\)]], ". The slope of the normal line ", Cell[BoxData[ \(TraditionalForm\`\(P\_0\) P\)]], " at ", Cell[BoxData[ \(TraditionalForm\`P\)]], " can be obtained by taking the negative reciprocal of this: \n\n \ slope of ", Cell[BoxData[ \(TraditionalForm\`\(P\_0\) P\)]], " = ", Cell[BoxData[ \(TraditionalForm \`\(a\^2\) y/\((\(b\^2\) x)\) |\_\((a\ Cos\ \[Theta], \ b\ Sin\ \[Theta])\)\)]], " = ", Cell[BoxData[ \(TraditionalForm\`a\ Sin\ \[Theta]\ /\ \((b\ Cos\ \[Theta])\)\)]], " \t (1.4)\n\nOne can set the right-hand \ sides of equations (1.2) and (1.4) equal to each other and simplify to obtain \ the following equation:\n\n \ ", Cell[BoxData[ \(TraditionalForm \`\(x\_0\)(a\ Sin\ \[Theta]) - \(y\_0\)(b\ Cos\ \[Theta]) = \((a\^2 - b\^2)\)\ Sin\ \[Theta]\ Cos\ \[Theta]\)]], " \t (1.5)\n\nIt is important to \ realize that for given values ", Cell[BoxData[ \(TraditionalForm\`a, \ b, \ x\_0\)]], " and ", Cell[BoxData[ \(TraditionalForm\`y\_0\)]], ", the number of distinct solutions for \[Theta] of the above equation \ (1.5) where 0 \[LessEqual] \[Theta] < 2\[Pi] , correspond to the number of \ distinct normal lines that can be drawn from ", Cell[BoxData[ \(TraditionalForm\`\(P\_0\)(x\_0, y\_0)\)]], " to the ellipse. In order to solve the equation (1.5), we will consider \ two cases:\n\n", StyleBox["Case 1: ", FontWeight->"Bold"], Cell[BoxData[ \(TraditionalForm\`y\_0 = 0\)]], " \n In this case, the equation (1.5) will imply that ", Cell[BoxData[ \(TraditionalForm\`\(\ Sin\ \[Theta] = 0\)\)]], " or ", Cell[BoxData[ \(TraditionalForm \`Cos\ \[Theta] = a\ x\_0/\((a\^2 - b\^2)\)\_\(\ \)\)]], ". The equation Sin \[Theta] = 0 implies that ", Cell[BoxData[ \(TraditionalForm\`P = \((a, 0)\)\)]], " or ", Cell[BoxData[ \(TraditionalForm\`\((\(-a\), 0)\)\)]], ". Therefore, these two values for ", Cell[BoxData[ \(TraditionalForm\`P\)]], " will correspond to two distinct normal lines (along the ", Cell[BoxData[ \(TraditionalForm\`X\)]], "-axis). However, the equation ", Cell[BoxData[ \(TraditionalForm\`Cos\ \[Theta] = a\ x\_0/\((a\^2 - b\^2)\)\)]], " will produce real values for \[Theta] if and only if ", Cell[BoxData[ \(TraditionalForm \`\(| x\)\_0 | \( \[LessEqual] \((a\^2 - b\^2)\)/a\) = a\ e\^2\)]], " where ", Cell[BoxData[ \(TraditionalForm\`e = \@\(a\^2 - b\^2\)/a\)]], " is the eccentricity of the ellipse. If ", Cell[BoxData[ \(TraditionalForm\`\(\(| x\)\_0 | \( < \((a\^2 - b\^2)\)/a\), \)\)]], " then we obtain two distinct values of \[Theta] such that ", Cell[BoxData[ \(TraditionalForm\`Cos\ \[Theta] = a\ x\_0/\((a\^2 - b\^2)\)\)]], " with 0 \[LessEqual] \[Theta] < 2\[Pi] and ", Cell[BoxData[ \(TraditionalForm\`\[Theta] \[NotEqual] \[Pi]\)]], ", corresponding to two more distinct normal lines. On the other hand, if \ ", Cell[BoxData[ \(TraditionalForm\`\(\(| x\)\_0 | \) = \((a\^2 - b\^2)\)/a\)]], ", then we obtain the previous normal lines ", Cell[BoxData[ \(TraditionalForm\`\(P\_0\) P\)]], " along the ", Cell[BoxData[ \(TraditionalForm\`X\)]], "-axis with ", Cell[BoxData[ \(TraditionalForm\`P = \((a, 0)\)\)]], " or ", Cell[BoxData[ \(TraditionalForm\`\((\(-a\), 0)\)\)]], " Hence one can conclude that the case ", Cell[BoxData[ \(TraditionalForm\`y\_0 = 0\)]], " corresponds to two or four distinct normal lines according as ", Cell[BoxData[ \(TraditionalForm\`\(| x\)\_0 | \( \[GreaterEqual] a\ e\^2\)\)]], " or ", Cell[BoxData[ \(TraditionalForm\`\(| x\)\_0 | \( < \ a\ e\^2\)\)]], ".\n\n", StyleBox["Case 2:", FontWeight->"Bold"], " ", Cell[BoxData[ \(TraditionalForm\`y\_0 \[NotEqual] 0\)]], ".\n This case implies, via equation (1.5) that \[Theta] \[NotEqual] \ \[Pi]. Therefore, ", Cell[BoxData[ \(TraditionalForm\`Tan\ \((\[Theta]/2)\)\)]], " is well defined. Therefore, let us use the trigonometric substitution ", Cell[BoxData[ \(TraditionalForm\`t = Tan\ \((\[Theta]/2)\)\)]], " to solve equation (1.5) (see [3]). One can easily show that ", Cell[BoxData[ \(TraditionalForm\`Sin\ \[Theta] = 2 t/\((1 + t\^2)\)\)]], " and ", Cell[BoxData[ \(TraditionalForm\`Cos\ \[Theta] = \((1 - t\^2)\)/\((1 + t\^2)\)\)]], ". Substitute these expressions back in equation (1.5) and simplify to \ obtain\n \n ", Cell[BoxData[ \(TraditionalForm \`\(t\^4\)(b\ y\_0) + 2 \( t\^\(3\ \)\)[a\ x\_0 + \((a\^2 - b\^2)\)]\ + 2 t\ [a\ x\_0 - \((a\^2 - b\^2)\)] - b\ y\_0 = 0\_\(\ \)\)]], " (1.6)\n \nThe ", StyleBox["\"Solve\"", FontWeight->"Bold"], " command of ", StyleBox["Mathematica", FontSlant->"Italic"], " can certainly solve the above equation (1.6) for ", Cell[BoxData[ \(TraditionalForm\`t\)]], " . However, as the reader can verify, these solutions are almost useless, \ because of their complexity. Rather than the actual solutions themselves, at \ this point we are more interested in the nature or the number of solutions. \ Therefore, we will proceed as follows: One can further simplify equation \ (1.6). Since ", Cell[BoxData[ \(TraditionalForm\`a\^2 - b\^2 = a\^2\ e\^2\)]], ", the equation (1.6) will read\n\n \ ", Cell[BoxData[ \(TraditionalForm \`\(t\^4\)(b\ y\_0) + 2\ a\ \(t\^\(3\ \)\)[\ x\_0 + a\ e\^2]\ + 2\ a\ t\ [\ x\_0 - a\ e\^2] - b\ y\_0 = 0\_\(\ \)\)]], " (1.7)\n\nSince ", Cell[BoxData[ \(TraditionalForm\`y\_0 \[NotEqual] 0\)]], " , the above equation (1.7) represents a quartic equation with real \ coefficients. Notice that we have transformed the trigonometric equation \ (1.5) to a polynomial equation (1.7). The discriminant of the quartic \ equation (1.7) reveals the nature of its roots.\n\nRecall that the \ discriminant of the quartic ", Cell[BoxData[ \(TraditionalForm \`\[Phi](x) = \(a\_0\) x\^4 + 4 \( a\_1\) x\^3 + 6 \( a\_2\) x\^2 + 4 \( a\_3\) x + a\_4\)]], " with roots ", Cell[BoxData[ \(TraditionalForm\`p, q, r\)]], " and ", Cell[BoxData[ \(TraditionalForm\`s\)]], " are given by (see [1]) \n ", Cell[BoxData[ \(TraditionalForm \`d = a\_0\%6\ \(\((p - q)\)\^2\) \(\((p - r)\)\^2\) \(\((p - s)\)\^2\) \(\((q - r)\)\^2\) \(\((q - s)\)\^2\) \((r - s)\)\^2\)]], " \t\t (1.8)\n \nOne \ can also obtain the following version for the discriminant in terms of the \ coefficients of the quartic (see [1]):\n\n ", Cell[BoxData[ \(TraditionalForm \`d = 256\ [ \((\(a\_0\) a\_4 - 4 \( a\_1\) a\_3 + 3 a\_2\^2)\)\^3 - 27 \((\(a\_0\) \(a\_2\) a\_4 + 2 \( a\_1\) \(a\_2\) a\_3 - \(a\_0\) a\_3\^2 - \(a\_4\) a\_1\^2 - a\_2\^3)\)\^2]\)]], " (1.9)\n\nUsing the Intermediate Value Theorem in calculus, one \ can easily see that our equation (1.7) has at least two distinct real roots \ (see [17]). Call these two real roots \[Alpha] and \[Beta] , and the other \ two roots \[Gamma] and \[Delta]. The equation (1.8) implies that the \ discriminant ", Cell[BoxData[ \(TraditionalForm\`D\)]], " of the quartic (1.7) is given by\n \n \ ", Cell[BoxData[ \(TraditionalForm\`\(D = \)\)]], Cell[BoxData[ \(TraditionalForm \`\((b\ y\_0)\)\^6\ \(\((\[Alpha] - \[Beta])\)\^2\) \(\((\[Alpha] - r)\)\^2\) \(\((\[Alpha] - \[Delta])\)\^2\) \(\((\[Beta] - \[Gamma])\)\^2\) \(\((\[Beta] - \[Delta])\)\^2\) \((\[Gamma] - \[Delta])\)\^2\)]], "\t\t\t (1.10)\n \nCase (a): Suppose the equation (1.7) has \ exactly two distinct real roots. Then \n (i) \[Gamma] and \ \[Delta] are real \[DoubleRightArrow] ", Cell[BoxData[ \(TraditionalForm\`D = 0\)]], " (ii) \[Gamma] and \[Delta] are non real \ \[DoubleRightArrow] ", Cell[BoxData[ \(TraditionalForm\`D < 0\)]], ".\n\nCase (b): Suppose the equation (1.7) has exactly three distinct real \ roots. Then clearly ", Cell[BoxData[ \(TraditionalForm\`D = 0\)]], ". \n \nCase (c): Suppose that the equation (1.7) has \ exactly four distinct real roots. Then clearly ", Cell[BoxData[ \(TraditionalForm\`D > 0\)]], ".\n \nLet us now calculate ", Cell[BoxData[ \(TraditionalForm\`D\)]], " in terms of the coefficients of (1.7). By comparing the polynomial ", Cell[BoxData[ \(TraditionalForm \`\[Phi](x) = \(a\_0\) x\^4 + 4 \( a\_1\) x\^3 + 6 \( a\_2\) x\^2 + 4 \( a\_3\) x + a\_4\)]], " with the left-hand side of equation of (1.7), one finds that ", Cell[BoxData[ \(TraditionalForm\`a\_0 = b\ y\_0, \ a\_1 = \(a(x\_0 + a\)\)]], Cell[BoxData[ \(TraditionalForm\`\(e\^2)\)/2, \ a\_2 = 0, \ a\_3 = \(a(x\_0 - a\ e\^2)\)/2\)]], " and ", Cell[BoxData[ \(TraditionalForm\`a\_4 = \(-b\)\ \(y\_0 . \)\)]], " Therefore, equation (1.9) implies that\n\n ", Cell[BoxData[ \(TraditionalForm \`D = \(D(x\_0, y\_0) = 256\ {\ \([\ \((a\^2 - b\^2)\)\^2 - \(a\^2\) x\_0\^2 - \(b\^2\) y\_0\^2]\)\^3 - 27 \( a\^2\) \(\(b\^2\)(a\^2 - b\^2)\) \(x\_0\^2\) y\_0\^2} \)\)]], " \t (1.11)\n\nOne can use ", StyleBox["Mathematica", FontSlant->"Italic"], " for simplification purposes to arrive at the above equation. Depending \ on the values of ", Cell[BoxData[ \(TraditionalForm\`x\_0\)]], " and ", Cell[BoxData[ \(TraditionalForm\`y\_0\)]], ", ", Cell[BoxData[ \(TraditionalForm\`D(x\_0, y\_0)\)]], " could be positive (i.e. 4 distinct normals), negative (i.e. 2 distinct \ normals) , or zero (i. e. 2 or 3 normals). To find out when does this \ happen, one can draw the graph of the following equation:\n\n \ ", Cell[BoxData[ \(TraditionalForm \`f(x, y) = \ \(\([\ \((a\^2 - b\^2)\)\^2 - \(a\^2\) x\^2 - \(b\^2\) y\^2]\)\^3 - 27 \( a\^2\) \(\(b\^2\)(a\^2 - b\^2)\) \(x\^2\) y\^2 = 0\)\)]], " (1.12)\n \nFor given \ specific values of ", Cell[BoxData[ \(TraditionalForm\`a\)]], " and ", Cell[BoxData[ \(TraditionalForm\`b\)]], " one can use the ", StyleBox["\"ImplicitPlot\"", FontWeight->"Bold"], " command of ", StyleBox["Mathematica", FontSlant->"Italic"], " to see the shape of the graph given by equation (1.12). In general, one \ can show that the equation (1.12) has the following parametrization:\n\n \ ", Cell[BoxData[ \(TraditionalForm \`x = \([\((a\^2 - b\^2)\)\ \(Cos\^3\) \[Alpha]]\)/a\)]], " and ", Cell[BoxData[ \(TraditionalForm \`y = \([\((a\^2 - b\^2)\) \(Sin\^3\) \[Alpha]]\)/b\)]], " ; 0 \[LessEqual] \[Alpha] < 2\[Pi] (1.13) \ \n \nFor ", Cell[BoxData[ \(TraditionalForm\`a = 6\)]], " and ", Cell[BoxData[ \(TraditionalForm\`b = 4\)]], " , the following ", StyleBox["Mathematica", FontSlant->"Italic"], " command ", StyleBox["\"ParametricPlot\"", FontWeight->"Bold"], " produces the graph of equation (1.13):" }], "Text", CellMargins->{{9, Inherited}, {Inherited, Inherited}}, TextAlignment->Left, TextJustification->1], Cell[CellGroupData[{ Cell[BoxData[ \(\(\ a = 6; \ b = 4; \n\ ParametricPlot[{\((a^2 - b^2)\) Cos[alpha]^3/a, \((a^2 - b^2)\) Sin[alpha]^3/b}, \n\ \ \ \ \ \ \ \ {alpha, 0, 2 Pi}, \ AspectRatio -> Automatic, \ Ticks -> None]\)\)], "Input", TextAlignment->Left, 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Cell[TextData[{ "Observe that the above graph is quite similar to the astroid ", Cell[BoxData[ \(TraditionalForm\`x\^\(2/3\) + y\^\(2/3\) = \ c\^\(2/3\)\)]], " where ", Cell[BoxData[ \(TraditionalForm\`\(\ c\)\)]], " is a constant (see [20]). Motivated by this, it is not hard to show that \ any of the equations (1.12) or (1.13) is equivalent to the following \ equation, which we will refer to as the \"generalized astroid\":\n\n \ ", Cell[BoxData[ \(TraditionalForm \`\((x\ a)\)\^\(2/3\) + \((y\ b)\)\^\(2/3\) = \((a\^2 - b\^2)\)\^\(2/3\)\)]], " (1.14)\n\n\ Using the above graph, one sees that if (", Cell[BoxData[ \(TraditionalForm\`\(x\_0, y\_0)\)\)]], " is inside the curve, then ", Cell[BoxData[ \(TraditionalForm\`D(x\_0, y\_0)\)]], " is positive; If (", Cell[BoxData[ \(TraditionalForm\`\(x\_0, y\_0)\)\)]], " is on the curve, then ", Cell[BoxData[ \(TraditionalForm\`D(x\_0, y\_0)\)]], " is equal to zero; If (", Cell[BoxData[ \(TraditionalForm\`\(x\_0, y\_0)\)\)]], " is outside the curve, then ", Cell[BoxData[ \(TraditionalForm\`D(x\_0, y\_0)\)]], " is negative. \n\nOne can now combine the outcomes of cases 1 and 2 in \ this section to arrive at the following conclusion: If ", Cell[BoxData[ \(TraditionalForm\`P\_0\)]], " is inside the generalized astroid, then one can draw four distinct normal \ lines from to the ellipse; If ", Cell[BoxData[ \(TraditionalForm\`P\_0\)]], " is outside the generalized astroid, then one can draw two distinct normal \ lines from ", Cell[BoxData[ \(TraditionalForm\`P\_0\)]], " to the ellipse; If ", Cell[BoxData[ \(TraditionalForm\`P\_0\)]], " is on the generalized astroid, but not a cusp point, then one can draw \ three distinct normal lines from ", Cell[BoxData[ \(TraditionalForm\`P\_0\)]], " to the ellipse; If ", Cell[BoxData[ \(TraditionalForm\`P\_0\)]], " is one of the four cusp points on the generalized astroid, then one can \ draw two distinct normal lines from ", Cell[BoxData[ \(TraditionalForm\`P\_0\)]], " to the ellipse. 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.13847 m .57692 0 L s .48846 1 m .5 .90929 L .56526 .3961 L s .56526 .3961 m .61564 0 L s .4835 1 m .5 .90358 L .56526 .5223 L .62941 .14755 L s .62941 .14755 m .65467 0 L s .47753 1 m .5 .89627 L .56526 .59498 L .62941 .29885 L .69134 .01294 L s .69134 .01294 m .69414 0 L s .47028 1 m .5 .88741 L .56526 .64015 L .62941 .39713 L .69134 .1625 L s .69134 .1625 m .73423 0 L s .46142 1 m .5 .87701 L .56526 .66897 L .62941 .4645 L .69134 .26708 L .75 .0801 L s .75 .0801 m .77513 0 L s .45057 1 m .5 .86513 L .56526 .68706 L .62941 .51204 L .69134 .34305 L .75 .18301 L .80438 .03463 L s .80438 .03463 m .81707 0 L s .4373 1 m .5 .8518 L .56526 .69755 L .62941 .54593 L .69134 .39954 L .75 .2609 L .80438 .13236 L .85355 .01614 L s .85355 .01614 m .86038 0 L s .42109 1 m .43474 .97183 L .5 .83709 L .56526 .70235 L .62941 .56992 L .69134 .44205 L .75 .32095 L .80438 .20867 L .85355 .10715 L .89668 .01812 L s .89668 .01812 m .90545 0 L s .4013 1 m .43474 .93938 L .5 .82105 L .56526 .70271 L .62941 .5864 L .69134 .47411 L .75 .36775 L .80438 .26915 L .85355 .17999 L .89668 .1018 L .933